3[2y-3]=5[y-2]

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Solution for 3[2y-3]=5[y-2] equation:


Simplifying
3[2y + -3] = 5[y + -2]

Reorder the terms:
3[-3 + 2y] = 5[y + -2]
[-3 * 3 + 2y * 3] = 5[y + -2]
[-9 + 6y] = 5[y + -2]

Reorder the terms:
-9 + 6y = 5[-2 + y]
-9 + 6y = [-2 * 5 + y * 5]
-9 + 6y = [-10 + 5y]

Solving
-9 + 6y = -10 + 5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-5y' to each side of the equation.
-9 + 6y + -5y = -10 + 5y + -5y

Combine like terms: 6y + -5y = 1y
-9 + 1y = -10 + 5y + -5y

Combine like terms: 5y + -5y = 0
-9 + 1y = -10 + 0
-9 + 1y = -10

Add '9' to each side of the equation.
-9 + 9 + 1y = -10 + 9

Combine like terms: -9 + 9 = 0
0 + 1y = -10 + 9
1y = -10 + 9

Combine like terms: -10 + 9 = -1
1y = -1

Divide each side by '1'.
y = -1

Simplifying
y = -1

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